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The balanced distribution type 4333/4432 is known with the bid of 2 in most of the sequences.
Relayer has several ways to progress the bidding. In case of game-level he can define that he or partner will play or and at the same time he can ask for a 3 or 4 card Major. So in case no 3 or 4cM , 3NT in the proper hand.
Or he can ask for stopper(s).

2 -	?
Bid	Level	Description
[2]	game or +	relay
{2}	game	in case there was no bid in the sequence, R is able now to play the -contract òr if there was no bid RR is able to play the contract.See survey If no need then use the [2] relay or in case of a 5card Major bid your suit {2} asks at the same time for 4card M and if R has a 5card M he can ask for a 3card support later in case no 4M	3= 4cM, but 4333 OR 434m2	{3} = call your 4cM	3=434m2	[3],3, ES, Slab
					3= 4333	3, ES, Slab
					3= 4333	Pass, ES, Slab
				3 = CP 3 = CAB 3 = to play rest = SLab
			3= no 4cM	{3} = call your 3crd. M	3=or / * and 3= « 3244 »
				[3] = relay and minor orientated	3= 4m333	[4], ES, SLab
					4= « 2344 »	ES, Slab
					4= « 3244 »	4! =ES, Slab
						in a 0-3p. no King setting all bids are Slab's and 5m afterwards = to play normally
				3 , ES, Slab
			3= 4c+ 4cm	3] = kind of distri relay (-fit?)	3= 2c	Pass, [4], ES, SLab
					4= « 3424 »	ES, Slab
					4= « 3442 »	4M =to play,rest=Slab
				3 , ES, Slab
			3= 4c+ 4cm, 2c	[4]= relay	4= « 4234 »	4! =ES, Slab
					4= « 4243 »	4 =to play,rest=Slab
	With the [2] relay you still have the possibility to ask for the exact distribution, specially done in case this relay is after a 0-3p. 4333/4432 2 bid and thus the ONLY relay left, reason for the bids higher as 3			3 , ES, SLab
			3= « 4423»	pass, ES, SLab
			4= « 4432» no Q	ES, 4! =Sab (so every next step=SAB, rest = to play) - see example
			4= «4432» Qno Q	4M= to play, 4= Q?
			4= «4432» Q+ Q	4M= to play, 4= J?
{3}	game	stopper ask and/òr for a Major		3 = no stop	{3} = stop ?	3 = 1/2 stop - then{ 4} = * 3 = stop - then{ 4} = ** 4 =ONE 3/4c M 4 =33 or 43 in the M 4 =44 in the M
					{3} = stop ?	3 = stop - then{ 4} = ** 4 =ONE 3/4c M 4 =33 or 43 in the M 4 =44 in the M
				3 = stop, no stop	{3} = stop ?	3 = stop - then{ 4} = ** 4 =ONE 3/4c M 4 =33 or 43in the M 4 =44 in the M
				3 = stop, stop, no	{ * 4 } =asking for RR's Majors if no distri known, otherwise normal distri relay	4 =33 or 43 or 44 in the M 4 =4c , 2c 4 =4c , 2c
					{4 } = 33 or 43 in the Majors {4 } = 44 in the Majors
				3 = stop, + stop	{ ** 4 } =asking for RR's Majors if no distri known, otherwise (always if you wish) normal distri relay	4 =33 or 43 or 44 in the M 4 =4c , 2c 4 =4c , 2c
					{4 }=End Signal {4 }=Slam asking Bid
{3}	game	stopper ask prior in and if yes further info (in case of a 0-5p. Asking for both minors, so not prior )		3 = no stop	{3} = 1/2 stopper in 3card ? 3} = 1/2 stopper in doubleton ?
					{ * 4 } =asking for RR's Majors if no distri known , otherwise normal distri relay	4 =33 or 43 or 44 in the M 4 =4c , 2c 4 =4c , 2c
					{4 } = 33 or 43 in the Majors {4 } = 44 in the Majors
				3 = stop, no stop
				3 = stop, stop
{3}	game	3 (or 4) card ? (with 5M4M use the relays)			3 = no and 4= yes
{3}	game	3 (or 4) card ? (with 5M4M use the relays)			3 = no and 4 =yes
3	game	to play
4	game	« 4441 » = pick a game (incl. 4)
4	game	« 4414 » = pick a game (incl. 4)
4	game	« 1444 » = pick a game (incl. 4)
4	game	« 4144 » = pick a game (incl. 4)
* for the sake of good order : if after 2- {2} 3- {3} 3 -3 (3= or /) you have to bid 4 with 33M (RR has a 5 c because of his {3}relay) and 3 -[4]= relay : 4 = « 3334 » , 4 = « 2344 » , 4 = « 3343 »

regarding stopperbids: used in balanced suits/ singleton too; for total stopper-bids see survey.

Answers after the [2] relay:
the bids 2-3 are transfers to the lowest 4-card; again a relay, then other 4 card on real level or preferable through the transfer/reverted scheme.It depends on the level if a further relay is needed or not if you want to know the exact distribution. Because of the limited numbers of bidding steps there are two 4 level bids unfortunately (if asked for full distribution) and those have always a 3-card in spades)

2 -	[2]
?
Bid	Shape	Description
2	4432	4 + 4 other	[3] {3} is stopper M asking*)	3 = (or alternative**)	[3]	3 = ‹‹ 2344 ›› 3 = ‹‹ 3244 ››		3, endsignal, slab pass, endsignal, slab
				3 = (or alternative**)	[3]	3 = ‹‹ 2434 ›› 4 = ‹‹ 3424 ››		pass, endsignal, slab endsignal, slab
				3 = ‹‹ 4234 ›› 3 = ‹‹ 4324 ›› (or alternative**)	3, endsignal, slab pass, endsignal, slab
3	4432	4 + 4 Major	[3]	3 = (or alternative**)	[3]	3 = ‹‹ 2443 ›› 4 = ‹‹ 3442 ››		pass, endsignal, slab endsignal, slab
				3 = ‹‹ 4243 ›› 3 = ‹‹ 4342 ›› or the alternative**		3, endsignal, slab pass, endsignal, slab
3	4432	4 + 4	[3]	3 = ‹‹ 4423 ›› 3 = ‹‹ 4432 ››		(3), endsignal, slab pass, endsignal, slab
3	4333	4 or 4	[3]	3 = 4333 4 = 4333		endsignal, slab 4 End Signal and then 4 = "scan" , min or max? -Pass = minimum -5 etc= Scan AK and a max (4c and the ususal order)
				4 = 4333 18-19p. 4 = 4333 18-19p.		4} ! = endsignal, slab 4} ! = endsignal, slab
			3	4 = 4333 18-19p. 4 = 4333 18-19p.		endsignal, slab (4 after ES = to play!) 4} ! = endsignal, slab (4 after ES = to play!)
			4 =slab so not interested in 3 or 4 card 4 =slab so not interested in 3 or 4 card Following up to you, but in the framework of this system a possibility: In case of a 13-15 pointrange: 4 ="scan" , min or max? 4, 5 etc= Scan AK and a max ( order) , 4= minimum 4 ="scan" , not so interested in min/max (= willing to play 5) ( order) 4 ="scan" , not so interested in min/max (= willing to play 5) ( order) 5 ="scan" , not so interested in min/max (= willing to play 5) ( order) 5 ="scan" , not so interested in min/max (= willing to play 5) ( order) in the 4/5 bids every bid is to play and not "scan further" ! So NT= always the end contract. In case of other pointranges (= with a margin of 1 point): 4 ="scan" , = willing to play 5 ( order) so after 4: 4 = scan further! 4 ="scan" , = willing to play 5 ( order !!) 4 ="scan" , = willing to play 5 ( order) 5 ="scan" , = willing to play 5 ( order) 5 ="scan" , = willing to play 5 ( order) in the 4/5 bids every bid is to play and not "scan further" ! So NT= always the end contract. (through relay [3],4 End Signal and then 4 = scan (4c and the usual order)
			• In this way you have 2 possibiities for the 13-15 pointrange: 1) first infoming min or max and the possibility to stop in 4. If a max you had influence in the scan order by bidding - 4 directly ( the usual order) - or through the distribution relay [3] and the End Signal and thèn 4 (4c+ usual order) 2) if a max is not so important (= willing to play 5) - through directly bidding 4 (= scan order ) - through directly bidding 4 (= scan order ) - through directly bidding 5 (= scan order ) - through directly bidding 5 (= scan order ) - through bidding 4 , negative 4 bid and then 5= scan in order (in case of a positive answer you can't use that order) • And for the 1 point margin in other pointranges (so a max or min is no issue) you have the same influence in the scan order (but now including the in order)
3	4333	4333 = numerical OR play if & are called already = 4333 In case of a 13-15 pointrange: 4 End Signal and then 4 = Pass with a minimum, scan with a maximum ( and the usual order), so a direct scan is not possibile unfortunately In case of other pointranges: 4 End Signal and then 4 = scan (4c and the usual order)
3	4333	4333 = numerical OR play if & are called already = 4333 In case of a 13-15 pointrange: 4 End Signal and then 4 = Pass with a minimum, scan with a maximum (4c and the usual order), so a direct scan is not possibile unfortunately In case of other pointranges: 4 End Signal and then 4 = scan (4c and the usual order)
4	4333 18 or 19p.	4333, in case you don't look if & are mentioned before AND in both possibilities: 18-19 points (see example)				4} End Signal	4	then 4= to play!
						SLab
* stopper asking in Majors with {3} , answers: 3 = no stop - then {3} = stopper ? 3 = stop, no stop 3 = + stop
after 2 and 3 and 3: the standard procedure: 2 - 3 = relay, 3= Majors stoppers asking, 3= CP, 3= start control bidding start with 3 - 3 = relay, 3= CP, 3= start control bidding start with 3 - 3 = relay, 3= start control bidding start with =slem interest OR to reach that R will be the declarer in a -contract If you do not play the 3as CP or the 3 bid as Control asking, then : 3 = partner bid 4 with a 3/4card support 3 = partner bid 4 with a 3/4card support, otherwise 3
** to reach that R will be the eventual declarer and you are not afraid of a slightly memory load, I would like to recommend the following scheme:

2 -	[2]
?		and reversed/transfered answers for the second 4-card, depending on previous sequence
Bid	Shape	Description
2	4432	4 + 4 other	[3]	If the suit already appeared by a bid in the previous sequence:
				3 =	[3]	3 = ‹ ‹2344 ›› 3 = ‹‹ 3244 ››	3, endsignal, slab pass, endsignal, slab
				and in case RR has a 4card Major: further If BOTH Majors already appeared by a bid in the previous sequence:
				3 =	[3]	3 = ‹‹ 2434 ›› 4 = ‹‹ 3424 ››	pass, endsignal, slab endsignal, slab
				3 = ‹‹ 4234 ›› 3 = ‹‹ 4324 ››	3, endsignal, slab pass, endsignal, slab
				and in case RR has a 4card Major: further If ONE Major only already appeared by a bid in the previous sequence:
				3 =	[3]	3 = ‹‹ 4234 ›› 4 = ‹‹ 4324 ››	pass, endsignal, slab endsignal, slab
				3 = ‹‹ 2434 ›› 3 = ‹‹ 3424 ››	3, endsignal, slab pass, endsignal, slab
				If the suit NOT already appeared by a bid in the previous sequence:
				3 = ‹‹ 2344 ›› 3 = ‹‹ 3244 ››	3, endsignal, slab pass, endsignal, slab
				and in case RR has a 4card Major: further If BOTH Majors already appeared by a bid in the previous sequence:
				3 =	[3]	3 = ‹‹ 2434 ›› 4 = ‹‹ 3424 ››	pass, endsignal, slab endsignal, slab
				3 =	[3]	3 = ‹‹ 4234 ›› 3 = ‹‹ 4324 ››	3, endsignal, slab pass, endsignal, slab
				and in case RR has a 4card Major: further If ONE Major only already appeared by a bid in the previous sequence:
				3 =	[3]	3 = ‹‹ 4234 ›› 4 = ‹‹ 4324 ››	pass, endsignal, slab endsignal, slab
				3 =	[3]	3 = ‹‹ 2434 ›› 3 = ‹‹ 4324 ››	3, endsignal, slab pass, endsignal, slab
				why not taking ONE scheme (the second one) for both possibilities regarding the Majors? Well I prefer to avoid an eventual lead/takeout double.
3	4432	4 + 4 Major	[3]	If BOTH Major suits already appeared by a bid in the previous sequence:
				3 =	[3]	3 = ‹‹ 2443 ›› 4 = ‹‹ 3442 ››	pass, endsignal, slab endsignal, slab
				3 = ‹‹ 4243 ›› 3 = ‹‹ 4342 ››		3, endsignal, slab pass, endsignal, slab
				If ONE Major only already appeared by a bid in the previous sequence:
				3 =	[3]	3 = ‹‹ 4243 ›› 4 = ‹‹ 4342 ››	pass, endsignal, slab endsignal, slab
				3 = ‹‹ 2443 ›› 3 = ‹‹ 3442 ››	3, endsignal, slab pass, endsignal, slab
3	4432	4 + 4	[3]	3 = ‹‹ 4423 ›› 3 = ‹‹ 4432 ››		(3), endsignal, slab pass, endsignal, slab
3	4333	4 or 4	[3]	3 = 4333 4 = 4333		endsignal, slab 4 End Signal and then 4 = "scan" , min or max? -Pass = minimum -5 etc= Scan AK and a max (4c and the ususal order) ,
				4 = 4333 18-19p. 4 = 4333 18-19p.		4} ! = endsignal, slab 4} ! = endsignal, slab
			3	4 = 4333 18-19p. 4 = 4333 18-19p.		endsignal, slab 4} ! = endsignal, slab
			4 =slab so not interested in 3 or 4 card 4 =slab so not interested in 3 or 4 card Following up to you, but in the framework of this system a possibility: In case of a 13-15 pointrange: 4 ="scan" , min or max? 4, 5 etc= Scan AK and a max ( order) , 4= minimum 4 ="scan" , not so interested in min/max (= willing to play 5) ( order) 4 ="scan" , not so interested in min/max (= willing to play 5) ( order) 5 ="scan" , not so interested in min/max (= willing to play 5) ( order) 5 ="scan" , not so interested in min/max (= willing to play 5) ( order) in the 4/5 bids every bid is to play and not "scan further" ! So NT= always the end contract. In case of other pointranges (= with a margin of 1 point): 4 ="scan" , = willing to play 5 ( order) so after 4: 4 = scan further! 4 ="scan" , = willing to play 5 ( order !!) 4 ="scan" , = willing to play 5 ( order) 5 ="scan" , = willing to play 5 ( order) 5 ="scan" , = willing to play 5 ( order) in the 4/5 bids every bid is to play and not "scan further" ! So NT= always the end contract. (through relay [3],4 End Signal and then 4 = scan (4c and the usual order)
			• In this way you have 2 possibiities for the 13-15 pointrange: 1) first infoming min or max and the possibility to stop in 4. If a max you had influence in the scan order by bidding - 4 directly ( the usual order) - or through the distribution relay [3] and the End Signal and thèn 4 (4c+ usual order) 2) if a max is not so important (= willing to play 5) - through directly bidding 4 (= scan order ) - through directly bidding 4 (= scan order ) - through directly bidding 5 (= scan order ) - through directly bidding 5 (= scan order ) - through bidding 4 , negative 4 bid and then 5= scan in order (in case of a positive answer you can't use that order) • And for the 1 point margin in other pointranges (so a max or min is no issue) you have the same influence in the scan order (but now including the in order)
3	4333	4333 (or if you want to keep in style: = 4c in case both Major suits are already mentioned, otherwise 4c) In case of a 13-15 pointrange: 4 End Signal and then 4 = Pass with a minimum, scan with a maximum (4c and the usual order), so a direct scan is not possibile unfortunately In case of other pointranges: 4 End Signal and then 4 = scan (4c and the usual order)
3	4333	4333 (or if you want to keep in style: = 4c in case both Major suits are already mentioned, otherwise 4c) In case of a 13-15 pointrange: 4 End Signal and then 4 = Pass with a minimum, scan with a maximum (4c and the usual order), so a direct scan is not possibile unfortunately In case of other pointranges: 4 End Signal and then 4 = scan (4c and the usual order),
4	4333 18 or 19p.	4333, in case both Major suits are already mentioned otherwise 4333 AND in both possibilities: 18-19 points				4} End Signal	4	then 4= to play!
						SLab
In case of a stopper or control asking and then proceeding with the further distribution stick to the normal 4333/4432 scheme, because of be able to stop in a game and of course the correct suit.
I admit you have to think it over carefully before you will give an answer on the second Relay, but by this way you keep the whole transfer design of the system intact. Up to you which one you like. See 2 example boards (pdf)
Regarding the 4333 shape and the extra given possibility in case of an 13-15: completely up to you! Experience is that this 4333 shape is the "hardest"; reason for giving you - although more memory strain - this more sophisticated tool. Otherwise: ES- and then 4 after the obliged 4bid is 6 Aces/2Queens for the 4c+ highest side suit in order; or if no 4c known the order too.

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In the double transfer balanced scheme (= the weaker pointranges 8-12 or 6-11) the 4333 is separated from the 4432
and besides a diviation in quality to be able to end in 2
4333 11-12 poor , medium or good
4432 11-12 poor or good

Therefore is above relay choise not valid always.
- After a second relay [= strong one after a negative] exact distribution with same answers as if there were given a [2]
- After a 2 non forcing bid by R, RR can bid above 11/12 4333/4432 in the folllwing way:
2 for the poor or good 4333
2 for the poor 4432

After 2 R, if not passing, is still be able to progress with same bids as from the
scheme {3-3}, 3
Exact distribution asking is out of question because there was no strong relay,
but the {2} relay of the scheme can used now by bidding

{3} - with the standard 3/3 answers

(the original 3 answer for 4M333 can not exist namely)

In case 4432 max. and good quality bid by 2 R can choose the kind of relay.

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Choise of Relay [2] or [2]

As mentioned it depends on the previous sequence before the 2 bid. In the whole setting up of the system the first relays after [Pass] are not designed that in a 13+ against 12+ situation transfer-bids are included. But nevertheless you (could) have for above relays a choise in case which hand will play or .

Underneath a survey in which sequences it appears:

SPADES:
[ PASS] - [1] - [1] - [1] - [1] - [2] - 2 = 4333,4432 16-17

[ PASS] - [1] - [1] - [1] - [2] - 2= 4432 8-9

NO TRUMP:
[ PASS] - [1] - [1] - [1] - [1] - [2] - [2] - 2= 4333, 4432 12-13

[1] - [1] - 2 = 4432 11-12 good

NO TRUMP and SPADES:
[ PASS] - [1] - [1] - 2= 4432 10-11 good

[ PASS] - [1] - [1] - [1] - [2] - [2] - 2 = 4333,4432 13-15

See survey for all the possible sequences with a 4333/4432 shape independent of strenght, by the central 2 bid or else

back to shape/balanced


back to search: 4333, 4432 separate schemes

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Example for slam investigation and final contract will be always NT
W	Jxx		AKQ	E
W/non	Axx		Jxxx
AKx			QJx
KJxx			AQT

13+ any shape	[Pass]	1	6-11 part balanced OR 12+ any shape
13+ balanced OR ++ else	[1]	1	12+ any shape
13-15 balanced any 4333/4432 OR a Major 5332, 5422, 6322 OR any 7222 no 2/3 toph. OR if solid no side Ace	2	[2]	relay
any 4333/4432	2	[2]	relay
4m333	3	4}	will be the contract, min or max? If max scan () otherwise Pass
A or K, non or AK (=step 2) and a max (4 = a minimum)	5	5
	Pass

Example for slam investigation and final contract will be always NT and with a max 5NT
W	Jxx		AKQ	E
W/non	AKQ		Jxxx
Kxx			QJx
Kxxx			AQT

13+ any shape	[Pass]	1	6-11 part balanced OR 12+ any shape
13+ balanced OR ++ else	[1]	1	12+ any shape
13-15 balanced any 4333/4432 OR a Major 5332, 5422, 6322 OR any 7222 no 2/3 toph. OR if solid no side Ace	2	[2]	relay
any 4333/4432	2	[2]	relay
4m333	3	4}	will be the contract, min or max? If max scan () otherwise Pass
non OR AK ànd a max	4	5}	a max, thus: scan further, not interested in
K or A + ànd Q, ànd J	5	6
	Pass

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Example 18-19 pointer and a 4333 shape in the PASS hand
W	AKxx		Qxxx	E
W/non	Axx		Kxx
Axx			QTx
Axx			KQJx
BBO forum

13+ any shape	[Pass]	1	6-11 part balanced OR 12+ any shape
13+ balanced OR ++ else	[1]	1	12+ any shape
16-17 balanced, 4333 up to 7222 (if 4333 16-19 points)	1	[2]	relay
any 4333/4432	2	[2]	relay
4333 AND 18-19p.	4	4}	SLam Asking Bid
5 Aces of 5	6	6
	Pass
WIth f.e. AKx, Axxx, Axx, Axx:
4333 16-19p.	3	3	to play
18-19p.	4	4}	End Signal
obliged bid	4	4	NOW to play, because partner forced you
	Pass
And in case you do look if & are called already - with the 1st hand: AKxx, Axx, Axx, Axx:
4333 16-19p.	3	4}	SLam Asking Bid
5 Aces of 5 thus the 19-pointer	5	6
	Pass
And in case you do look if & are called already - with the 2nd. hand: AKx, Axxx, Axx, Axx:
4333 18-19p.	4	4}	End Signal
obliged bid	4	4	NOW to play, because partner forced you
	Pass

above treatment (as well as for the 4m333 with 18-19p.) not done because of this example but already noticed internally in my personal files

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Example for slam investigation and final contract will be always NT
W	AKxxx		Qxxx	E
W/non	x		Jxxx
AKQxx			xxx
Ax			xx

13+ any shape	[Pass]	1	6-11 part balanced OR 0-5 any shape (no Ace OR K+anyQ)
+5+C or 4333/4432 23+	[1]	1	the 0-5 variant
++	[1]	2	-3p (no K), balanced 4333 op to 7222
g.f. relay	[2]	2	any 4333 or 4432 OR any 7222 with QJ in the 7-card
relay	[2]	4}	‹‹ 4432››, noQ
Q ?	4}	4	yes, no J
	6	pass
Relayer can inform for a stopper and stillit will be still possible to hear the 4-c and the exact distribution
		2	any 4333 or 4432 OR any 7222 with QJ in the 7-card
stopper asking (and/or Majors)	3}	3	no
stopper ?	3}	3	yes, full stopper (Q or QJ)
distribution relay, Major orientated	[4]	4	3/3, 4/3 or 4/4 Majors
distribution relay	[4]	5	‹‹ 4432››, no Q
	6	pass

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